a spherical charged conductor has surface charge density row.the electric field on its surface is E and electric potential of conductor is v.now the radius of the sphere is halved keeping the charge to be constant.the new values of electric field and potential would be

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Solution

Dear Student,

$c h a r g e r e m a i n c o n s \tan t l e t i t b e Q, l e t t h e r a d i u s b e r E = \frac{k Q}{r^{2}}, V = \frac{k Q}{r} n o w t h e r a d i u s b e h a l f b u t t h e c h a r g e r e m a i n c o n s \tan t E' = \frac{4 k Q}{r^{2}} = 4 E V' = \frac{2 k Q}{r} = 2 V R e g a r d s$

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a spherical charged conductor has surface charge density row.the electric field on its surface is E and electric potential of conductor is v.now the radius of the sphere is halved keeping the charge to be constant.the new values of electric field and potential would be

Dear Student, charge remain constant let it be Q, let the radius be r E=kQr2, V=kQrnow the radius be half but the charge remain constant E'=4kQr2=4E V'=2kQr=2VRegards