A spherical conductor of radius 2m is charged to a potential of 120 V. It is now placed inside another hollow spherical conductor of radius 6m. Calculate the potential to which the bigger sphere would be raised to?

20 V

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60 V

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80 V

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40 V

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Solution

The correct option is D 40 V
If charge acquired by the smaller sphere is Q then it’s potential $120 = \frac{k Q}{2}$ ............. (i)
Also potential of the outer sphere
$V = \frac{k Q}{6}$ ............. (ii)
From equation (i) and (ii) V = 40 volt

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A spherical conductor of radius 2m is charged to a potential of 120 V. It is now placed inside another hollow spherical conductor of radius 6m. Calculate the potential to which the bigger sphere would be raised to?

The correct option is D 40 VIf charge acquired by the smaller sphere is Q then it’s potential 120=kQ2 ............. (i) Also potential of the outer sphere V=kQ6 ............. (ii) From equation (i) and (ii) V = 40 volt

The correct option is D 40 V
If charge acquired by the smaller sphere is Q then it’s potential $120 = \frac{k Q}{2}$ ............. (i)
Also potential of the outer sphere
$V = \frac{k Q}{6}$ ............. (ii)
From equation (i) and (ii) V = 40 volt