Question

A spherical drop of water has $1mm$ radius. If the surface tension of the water is $50$ x ${10}^{-3}$$N/m$, then the difference of pressure between inside and outside the spherical drop is :

• A. $25$$N/m^2$
• B. $10000$$N/m^2$
• C. $100$$N/m^2$
• D. $50$$N/m^2$

Answer 1

Answer: (C)

$100$$N/m^2$

Pressure diff $P_{diff}=\frac{2T}{R}=\frac{2\times 50\times {10}^{-3}}{1\times {10}^{-3}}=100N{m}^{-2}$