Question

A spherical glass vessel has a cylindrical neck which is $4$ cm long and $2$ cm in diameter. The diameter of the spherical part is $6$ cm. Find the amount of water it can hold?

Answer 1

We have,

Radius of cylindrical part $=1cm$

Height of cylindrical part $=4cm$

Radius of spherical part $=3cm$

According to the question,

Amount of water that can be held $=$ Volume of cylindrical part $+$ volume of spherical part

$=\pi r^{2}h+\frac{4}{3}\pi r^3$

$=\pi \times 1{cm}^2\times 4cm+\frac{4}{3}\times \pi \times 3^3$

$=4\pi +36\pi$

$=40\pi c{m}^3$

Hence, this is the answer.