A spherical half of volume $1000 c m^{3}$ is subjected to a pressure of $10$ atmosphere. The change in volume is $10^{- 3} c m^{- 3}$ . If the ball is made of iron find its bulk modulus.(Atmospheric pressure $= 1 \times 10^{3} N m^{- 2})$

3 \times 10^{11} N / m^{2}

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2 \times 10^{11} N / m^{2}

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1 \times 10^{11} N / m^{2}

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4 \times 10^{11} N / m^{2}

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Solution

The correct option is C $1 \times 10^{11} N / m^{2}$
$△ V = 10^{- 2} c m^{3}$
$V = 1000 c m^{3}$
$P = 10 a t m$
$= 10 \times 10^{5} N m^{- 2}$
$B = \frac{P}{△ V / V}$
$= \frac{10 \times 10^{5} \times 1000}{10^{- 2}}$
$B = 10^{11} N m^{- 2}$

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A spherical half of volume 1000 cm3 is subjected to a pressure of 10 atmosphere. The change in volume is 10−3 cm−3. If the ball is made of iron find its bulk modulus.(Atmospheric pressure =1×103 Nm−2)

The correct option is C 1×1011 N/m2△V=10−2cm3V=1000cm3P=10atm=10×105Nm−2B=P△V/V=10×105×100010−2B=1011Nm−2

A spherical half of volume $1000 c m^{3}$ is subjected to a pressure of $10$ atmosphere. The change in volume is $10^{- 3} c m^{- 3}$ . If the ball is made of iron find its bulk modulus.(Atmospheric pressure $= 1 \times 10^{3} N m^{- 2})$

The correct option is C $1 \times 10^{11} N / m^{2}$
$△ V = 10^{- 2} c m^{3}$
$V = 1000 c m^{3}$
$P = 10 a t m$
$= 10 \times 10^{5} N m^{- 2}$
$B = \frac{P}{△ V / V}$
$= \frac{10 \times 10^{5} \times 1000}{10^{- 2}}$
$B = 10^{11} N m^{- 2}$