A spherical liquid drop of diameter 2 x 10-4 m is falling with a constant velocity through air under gravity-If the density of liquid is 500 kg-m3 and co-efficient of viscosity of air is 2 x 10-5 Ns-m2 nbsp- determine the terminal velocity of the drop and viscous force acting on it- Neglect the density of air -g-9-8 m-s2- nbsp-

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2D Motion as Two 1D Motions

A spherical l...

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A spherical liquid drop of diameter 2 x 10^-4 m is falling with a constant velocity through air under gravity.If the density of liquid is 500 kg/m³ and co-efficient of viscosity of air is 2 x 10^-5Ns/m², determine the terminal velocity of the drop and viscous force acting on it. Neglect the density of air (g=9.8 m/s²)

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0.04 mm

1.9 \times 10^{- 5} {Ns/m}^{2}

1.2 {kg/m}^{3}

1000 {kg/m}^{3}

g = 10 {m/s}^{2}

5 \times 10^{- 4} m/s

= \frac{18 \times 10^{- 5}}{5} {N.s/m}^{2}, g = 10 {m/s}^{2}

= 900 {kg/m}^{3}

5 \times 10^{- 4} m/s

= 3.6 \times 10^{- 5} {N-s/m}^{2}, g = 10 {m/s}^{2}

ρ_{o} = 900 {kg/m}^{3})

5 \times 10^{- 4} m/s

= 3.6 \times 10^{- 5} {N-s/m}^{2}, g = 10 {m/s}^{2}

ρ_{o} = 900 {kg/m}^{3})

5 \times 10^{- 4} m / s

\frac{18 \times 10^{- 5}}{5} N - s / m^{2}

m / s^{2}

m^{3}

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