Let the height of the object, ho = h
Then, height of the image, hI = −3h (Image formed is real)
-3h/h = -u/v
v/u = 3
Object distance, u = −9 c
v = 3 × (−9) = −27 c
Here, the negative sign indicates that an inverted image is formed at a distance of 27 cm in front of the concave mirror.