A spherical planet far out in space has a mass $M_{o}$ and diameter $D_{o}$ . A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to

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Solution

The correct option is C

$g = \frac{G M}{R^{2}} = \frac{G M_{o}}{(\frac{D_{o}}{2})^{2}} = \frac{4 G M_{o}}{D_{o}^{2}}$

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A spherical planet far out in space has a mass Mo and diameter Do. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to

The correct option is C g=GMR2=GMo(Do2)2=4GMoD2o

A spherical planet far out in space has a mass $M_{o}$ and diameter $D_{o}$ . A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to

The correct option is C

$g = \frac{G M}{R^{2}} = \frac{G M_{o}}{(\frac{D_{o}}{2})^{2}} = \frac{4 G M_{o}}{D_{o}^{2}}$