A spherical planet has a mass $M_{p}$ and diameter $D_{p}$ . A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity equal to:

4 G M_{p} m D_{P}^{2}

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4 G M_{p} / D_{p}^{2}

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G M_{p} m / D_{p}^{2}

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G M_{p} / D_{p}^{2}

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Solution

The correct option is B $4 G M_{p} / D_{p}^{2}$
Near the surface of spherical planet, acceleration due to gravity,
$g = \frac{G M_{p}}{R_{p}^{2}}$ here $D_{p} = \frac{R_{p}}{2}$
$∴ g = \frac{4 G M_{p}}{D_{p}^{2}}$

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A spherical planet has a mass Mp and diameter Dp . A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity equal to:

The correct option is B 4GMp/D2pNear the surface of spherical planet, acceleration due to gravity,g=GMpR2p here Dp=Rp2∴g=4GMpD2p

A spherical planet has a mass $M_{p}$ and diameter $D_{p}$ . A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity equal to:

The correct option is B $4 G M_{p} / D_{p}^{2}$
Near the surface of spherical planet, acceleration due to gravity,
$g = \frac{G M_{p}}{R_{p}^{2}}$ here $D_{p} = \frac{R_{p}}{2}$
$∴ g = \frac{4 G M_{p}}{D_{p}^{2}}$