A spherical shell first rolls and then slips down an inclined plane. The ratio of its acceleration in two cases will be :
A
53
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B
35
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C
1513
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D
1315
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Solution
The correct option is A53 The moment of inertia of hollow sphere is 23mr2 The ratio of acceleration is given as 12Iω2+12mv212mv2 ⇒12(23mr2)v2r2+12mv212mv2 ⇒13mv2+12mv212mv2=53