A spherical shell of lead whose external and internal diameters are respectively 24 cm and 18 cm, is melted and recast into a right circular cylinder 37 cm high. Find the diameter of the base of the cylinder.

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Solution

Vspherical shell = Vcylinder

=

(1728 - 729) = 37

999 = 37

4 ×333 =

36 =

r = 6cm.

Hence the diameter =12 cm

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A spherical shell of lead whose external and internal diameters are respectively 24 cm and 18 cm, is melted and recast into a right circular cylinder 37 cm high. Find the diameter of the base of the cylinder.

Vspherical shell = Vcylinder = (1728 - 729) = 37 999 = 37 4 ×333 = 36 = r = 6cm. Hence the diameter =12 cm

Vspherical shell = Vcylinder

=

(1728 - 729) = 37

999 = 37

4 ×333 =

36 =

r = 6cm.

Hence the diameter =12 cm