wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A spherical shell of radius Ra and a solid metal sphere of radius Rb(Ra>Rb)are kept apart and each is given a charge +Q

If the two are connected by a metal wire what is the relation between electric field on their surfaces and ratio between surface charge density

Open in App
Solution

Electric field inside a spherical metallic shell with charge on the surfaceis always zero.

When the sells are connected with a thin metal wire then electric potentials will be equal, say V
∴ 1/ 4πϵ0 QA/RA = 1 / 4 πϵ0 QB­/RB = V
As RA> RB therefore QA> QB­
As σA/σB
=>QA/4πR2A /QB/4πR2B
= R2B / R2A * 4πϵ0 RAV / 4πϵ0 RAV
∴σAB = RB / RA

Also EA = σA/ σB = RB/RA< 1 ∴ EA< EB

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Electric Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon