A spherical solid ball of volume V is made of a material of density ‘s $_{1}$ ’. It is falling through a liquid of density ‘s $_{2}$ ’ (s $_{2}$ < s $_{1}$ ) assume that the liquid applies a viscous force on the ball that is proportional to the square of its speed ‘v’, F_viscous = K · v $^{2}$ , The terminal speed of the ball is

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Solution

The correct option is A

Here, kv $^{2}$ $= V ρ_{1} g - v ρ_{2} g$

$v = \sqrt{\frac{V (ρ_{1} - ρ_{2}) g}{k}}$

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