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Question

A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The center of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point Q, and PO = OQ. The distance PO is equal to

A
5R
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B
3R
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C
2R
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D
1.5R
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Solution

The correct option is A 5R
Use lens maker formula for the curved surface and find u. and according to the question u=v.
Watch the next video for the solution.

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