The correct option is B 22 W
Given:
Radius of the Tungsten sphere, r=10−2 m
emissivity of Tungsten, e=0.3
Stephen's constant, σ=6.0×10−8 Wm−2 K−4
Surrounding Temperature, T1=300 K
Temperature of the tungsten sphere, T2=1000 K
Now,
Surface area of Tungsten sphere,A=4πr2
⇒A=4π(10−2)2= 4π×10−4 m2
Rate at which energy is emitted from the tungsten sphere,
(ΔQΔt)e=eσAT42
Rate at which energy is absorbed by the tungsten from the surrounding, (ΔQΔt)a=eσAT41
So, the rate at which electrical energy must be supplied to maintain it at constant temperature is equal to the net rate of heat loss from the sphere.
i.e. electrical power supplied
=(ΔQΔt)e−(ΔQΔt)a
P=eσA(T42−T41)
P=0.3×6×10−8×4π×10−4((1000)4−(300)4)
∴P=22.4 W≈22 W
Hence, (B) is the correct answer.