A spinner has 10 equally sized sections,4 of which are gray and 6 of which are blue. The spinner is spun twice. What's the probability that tge first spin lands on gray and tbe second spin lands on blue?

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Solution

Dear student
The probability that the first spin lands on blue = 6/10
The probability that the second spin lands on gray = 4/10
The probability that the first spin lands on blue and the second spin lands on gray is
(6/10)(4/10)=6/25
These events are independent, so you can just multiply the probabilities
Regards

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