A sports car covers a distance in 100 min, if it runs at a speed of 96 kmph on an average. The speed at which the car must run to reduce the time of journey to 80 min will be

80 kmph

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100 kmph

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120 kmph

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160 kmph

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Solution

The correct option is C
120 kmph

Time = $\frac{100}{60} h r = \frac{5}{3}$ hr

Speed = 96 kmph

Distance = S $\times$ T = 96 $\times \frac{5}{3}$ = 160 km

Time = $\frac{80}{60} h r = \frac{4}{3}$ hr

New speed = 160 $\times \frac{3}{4}$ kmph = 120 kmph

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A sports car covers a distance in 100 min, if it runs at a speed of 96 kmph on an average. The speed at which the car must run to reduce the time of journey to 80 min will be

The correct option is C 120 kmph Time = 10060hr=53 hr Speed = 96 kmph Distance = S×T = 96×53 = 160 km Time = 8060hr=43 hr New speed = 160×34 kmph = 120 kmph

The correct option is C
120 kmph

Time = $\frac{100}{60} h r = \frac{5}{3}$ hr

Speed = 96 kmph

Distance = S $\times$ T = 96 $\times \frac{5}{3}$ = 160 km

Time = $\frac{80}{60} h r = \frac{4}{3}$ hr

New speed = 160 $\times \frac{3}{4}$ kmph = 120 kmph