A spring 40 mm long is stretched by applying a force. If 10 N force is required to stretch the spring through 1 mm, then work done in stretching the spring through 40 mm is
A
24 J
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B
8 J
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C
56 J
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D
64 J
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Solution
The correct option is B8 J Force constant, k=Fx=100.001=10000 N/m=104 N/m
Work done =12kx2=12×104×(401000)2 =12×104×16104=8 J