A spring balance hanging in steady state inside a train moving on a straight track shows a reading of double the actual mass of an object. Calculate the acceleration of the train.
A
√5g
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B
√2g
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C
√6g
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D
√3g
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Solution
The correct option is D√3g FBD of object from accelerating frame assuming that train is moving rightward with the acceleration a and block will experience a pseudo force in leftward as shown in the figure. Fpseudo=ma
At equilibrium, Fnet=Kx ⇒Kx=√(mg)2+(ma)2 ⇒Fspring=m√g2+a2 According to question, Fspring=2mg ⇒m√g2+a2=2mg ⇒√g2+a2=2g ⇒g2+a2=4g2 ⇒a=√3g2=√3g