A spring balance hanging in steady state inside a train moving on a straight track shows a reading of double the actual mass of an object. Calculate the acceleration of the train.
A
√5g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
√6g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
√3g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D√3g FBD of object from accelerating frame assuming that train is moving rightward with the acceleration a and block will experience a pseudo force in leftward as shown in the figure. Fpseudo=ma
At equilibrium, Fnet=Kx ⇒Kx=√(mg)2+(ma)2 ⇒Fspring=m√g2+a2
According to question, Fspring=2mg ⇒m√g2+a2=2mg ⇒√g2+a2=2g ⇒g2+a2=4g2 ⇒a=√3g2=√3g