CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
485
You visited us 485 times! Enjoying our articles? Unlock Full Access!
Question

A spring balance has a scale that reads from 0 to 50kg. The length of the scale is 20cm. A block of mass m is suspended from this balance, when displaced and released, it oscillates with a period 0.5s. The value of m is (Take g = 10 m s2)

A
8 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16kg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
20kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 16kg
The 20cm length of the scaler reads upto 50kg.
F=mg=(50kg)(10ms2)=500N and x=20cm=0.2m
Spring constant, k=Fx=500N0.2m=2500Nm1
As T=2πmk
Squaring both sides, we get
T2=4π2mk
m=T2k4π=(0.5s)2×(2500Nm1)4×(3.14)2=16kg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Just an Average Point?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon