A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads $49 N$ when the lift is stationary. If the lift moves downward with an acceleration of $5 {m/s}^{2}$ , the reading of the spring balance will be (Take $g = 9.8 m / s^{2}$ )

49 N

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24 N

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74 N

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15 N

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Solution

The correct option is B $24 N$
When lift is stationary, tension in the string, $T = m g = 49 N \Rightarrow m = \frac{49}{g}$

Using Newton's second law,
$m (5) = m g - T_{1} \Rightarrow T_{1} = 49 - 5 m \Rightarrow T_{1} = 49 - 5 (\frac{49}{9.8})$
$\Rightarrow T_{1} = 49 - 5 \times 5 \Rightarrow T_{1} = 24 N$

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A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N when the lift is stationary. If the lift moves downward with an acceleration of 5 m/s2, the reading of the spring balance will be (Take g=9.8 m/s2)

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A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads $49 N$ when the lift is stationary. If the lift moves downward with an acceleration of $5 {m/s}^{2}$ , the reading of the spring balance will be (Take $g = 9.8 m / s^{2}$ )