A spring balance is attached to the ceiling of a lift. A man hangs is bag on the spring and the spring reads 49 N, when the lift is stationary. If the moves downward with an acceleration of 5 m/ $s^{2}$ , the reading of the spring balance will be

74 N

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15 N

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49 N

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24 N

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Solution

The correct option is D 24 N
Given,
$g = 9.8 m / s^{2}$
$a = 5 m / s^{2}$
When the lift is stationary, $m g = 49 N$
$m = \frac{49}{9.8} = 5 k g$
When lift moves downward then,
$F = m (g - a)$
$F = 5 (9.8 - 5) = 24 N$
The correct option is D.

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Similar questions

Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads

49 N

when the lift is stationary. If the lift moves downward with an acceleration of

5 {m/s}^{2}

, the reading of the spring balance will be (Take

g = 9.8 m / s^{2}

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Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the balance reads

49 N

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5 {m/s}^{2}

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Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring balance reads 49 N, when the lift is stationary. Determine the reading of the spring balance, if the lift moves downward with an acceleration of 5

m s^{- 2}

Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads

49 N

, when the lift is stationary. If the lift moves downward with an acceleration of

5 {m/s}^{2}

, the reading of the spring balance ( in

N

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A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of $5 m / s^{2}$ , the reading of the spring balance will be:

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A spring balance is attached to the ceiling of a lift. A man hangs is bag on the spring and the spring reads 49 N, when the lift is stationary. If the moves downward with an acceleration of 5 m/s2, the reading of the spring balance will be

The correct option is D 24 NGiven,g=9.8m/s2a=5m/s2When the lift is stationary, mg=49Nm=499.8=5kgWhen lift moves downward then,F=m(g−a)F=5(9.8−5)=24NThe correct option is D.

A spring balance is attached to the ceiling of a lift. A man hangs is bag on the spring and the spring reads 49 N, when the lift is stationary. If the moves downward with an acceleration of 5 m/ $s^{2}$ , the reading of the spring balance will be

The correct option is D 24 N
Given,
$g = 9.8 m / s^{2}$
$a = 5 m / s^{2}$
When the lift is stationary, $m g = 49 N$
$m = \frac{49}{9.8} = 5 k g$
When lift moves downward then,
$F = m (g - a)$
$F = 5 (9.8 - 5) = 24 N$
The correct option is D.