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Question

# A spring has natural length 40cm and spring constant 500N/m.A block of mass 1kg is attached at one end of the spring and other end of the spring is attached to ceiling. The block released from the position, where the spring has length 45cm, then

A
the block will perform SHM of amplitude 5cm
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B
the block will have maximum velocity 305cm/sec
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C
the block will have maximum acceleration 15m/s2
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D
the minimum potential energy of the spring will be zero
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Solution

## The correct options are B the block will have maximum acceleration 15m/s2 C the minimum potential energy of the spring will be zero D the block will have maximum velocity 30√5cm/secFrom the image it is clear that, the amplitude of SHM will be a=3cm, alsofrom the given data, ω=√km=10√5, thus maximum velocity vmax=aω=30√5cm−sec−1Accelerationmax=aω2=15m−sec−2Minimum potential energy is 0 at mean position.

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