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Question

# A spring is initially compressed by 2 m. Find out the work done required to compress another 6 m if spring constant k=2 N/m.

A
60 J
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B
32 J
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C
68 J
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D
36 J
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Solution

## The correct option is A 60 JWork done required to compress the spring = change in potential energy of spring Initial compression in spring x0=2 m Compression in spring when spring is compressed another 6 m is x1=6+2 x1=8 m Change in potential energy of spring =12kx21−12kx22 =12k[x12−x20] =12k[82−22]=60 J Therefore work done required =60 J

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