Question

A spring is stretched by 0.20 m, when a mass of 0.50 kg is suspended. When a mass of 0.25 kg is suspended, then its period of oscillation will be ( g = 10 m/$s^2$ )

• A. 0.328 sec
• B. 0.628 sec
• C. 0.137 sec
• D. 1.00 sec

Answer 1

The correct option is B

0.628 sec

Force constant k = $\frac{F}{x}=\frac{0.5\times 10}{0.2}=25N/m$

Now T = $2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{0.25}{25}}=0.628sec$