A spring is stretched by $0.20 m$ when a mass of $0.50$ kg is suspended. A mass of $0.25$ kg is suspended, then its period of oscillation will be ( $g = 10 m / s^{2}$ ) (approximately) .

0.628 s

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0.251 s

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6.28 s

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2.51 s

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Solution

The correct option is A $0.628 s$
Force $F = k x$
$\Rightarrow k = \frac{F}{x} = \frac{0.5 \times 10}{0.2} = 25 N / m$
$T = 2 π \sqrt{\frac{m}{k}} = 2 π \sqrt{\frac{0.25}{25}} = 0.628 s$

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A spring is stretched by 0.20m when a mass of 0.50 kg is suspended. A mass of 0.25 kg is suspended, then its period of oscillation will be (g=10m/s2) (approximately) .

The correct option is A 0.628sForce F=kx⇒k=Fx=0.5×100.2=25N/mT=2π√mk=2π√0.2525=0.628s

A spring is stretched by $0.20 m$ when a mass of $0.50$ kg is suspended. A mass of $0.25$ kg is suspended, then its period of oscillation will be ( $g = 10 m / s^{2}$ ) (approximately) .

The correct option is A $0.628 s$
Force $F = k x$
$\Rightarrow k = \frac{F}{x} = \frac{0.5 \times 10}{0.2} = 25 N / m$
$T = 2 π \sqrt{\frac{m}{k}} = 2 π \sqrt{\frac{0.25}{25}} = 0.628 s$