A spring mass system preforms S.H.M . If the mass is doubled keeping the amplitude same, then the total energy of S.H.M. will become:

double

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half

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unchanged

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4 times

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Solution

The correct option is C unchanged
The total energy of the mass spring system is equal to $\frac{1}{2} k A^{2}$ , which is independent of mass. So the total energy will remain unchanged if amplitude is kept the same.

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K

A

m

\begin{matrix} Column-I & Column-II (A) If mass of the block is doubled & (p) Time period increases (keeping K, A unchanged) (B) If the amplitude of oscillation is doubled & (q) Time period decreases (keeping K, m unchanged) (C) If force constant is doubled & (r) Energy of oscillation increases (keeping m, A unchanged) (D) If another spring of same force constant & (s) Energy of oscillation decreases is attached parallel to the previous one (keeping m, A unchanged) & (t) Energy of oscillation remain constant \end{matrix}

v

E

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