Question

A spring of force constant $800$ N/m has an extension of $5$ cm. Find work done in extending it from $5$ cm to $15$ cm.

Answer 1

$\text{Step 1: Expression for Work done by spring}$

Work done in stretching spring from length $x_1$ to $x_2$ is given by:

$W=\frac{1}{2}k(x_2^2-x_1^2)$

Where $k$ is the spring constant

$\text{Step 2: Calculations}$

Putting given values, we get:

$W=\frac{1}{2}\times 800N/m\left[\right(0.15m{)}^2-\left(0.05m{)}^2\right]$

$=8J$

Hence the work done in extending the spring from $5cm$ to $15cm$ is $8J.$