A spring of force constant k is cut in two parts at its one-third length. When both the parts are stretched by same amount. The work done in the two parts will be: (Note- Spring constant of a spring is inversely proportional to length of spring.)
A
equal in both
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B
greater for the longer part
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C
greater for the shorter part
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D
data insufficient
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Solution
The correct option is C greater for the shorter part As we know that spring constant k is inversely proportional to length of spring
kα1L
work done = change in potential energy
workdone=ΔPE=12kx2
so work done is directly proportional to k
it work done is inversely proportional to length
workdoneαkα1L
hence work done is more for small length of spring as compared to larger.