A spring of force constant $k$ , is cut into two equal parts, then the force constant of each piece is :

k

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k / 2

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4 / k

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2 k

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Solution

The correct option is D $2 k$
$k = \frac{E A}{l}$
When cut to two equal halves, new length $l_{1}$ becomes $l / 2$
$k_{1} = \frac{E A}{l_{1}} = \frac{2 E A}{l} = 2 k$

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A spring of force constant k, is cut into two equal parts, then the force constant of each piece is :

The correct option is D 2kk=EAlWhen cut to two equal halves, new length l1 becomes l/2k1=EAl1=2EAl=2k

A spring of force constant $k$ , is cut into two equal parts, then the force constant of each piece is :

The correct option is D $2 k$
$k = \frac{E A}{l}$
When cut to two equal halves, new length $l_{1}$ becomes $l / 2$
$k_{1} = \frac{E A}{l_{1}} = \frac{2 E A}{l} = 2 k$