A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of____
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Solution
Length of the spring = L Force constant of spring = K
Ratio in which spring is cut = 1 : 2 Length of larger piece = 2L / (2 + 1) = 2L/3 Force constant of larger piece = K’
Force constant ∝ 1 / Length of the spring
K / K’ = (2L / 3) / L K / K’ = 2 / 3 K’ = 3K / 2 K’ = 1.5 K Then the long piece will have a force constant of 1.5 k