A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the force constants of the pieces are

(\frac{2}{3}) k

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(\frac{3}{2}) k

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3 k

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6 k

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Solution

The correct option is B $(\frac{3}{2}) k$

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A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the force constants of the pieces are

The correct option is B (32)k

The correct option is B $(\frac{3}{2}) k$