Question

A spring toy weighing $1kg$ on a spring balance suddenly jumps upward. A boy standing near the toy notices that the scale of the balance reads $1.05kg$. In this process the maximum acceleration of the toy is $(g=10mse{c}^2)$:

• A. $0.05mse{c}^2$
• B. $0.5mse{c}^2$
• C. $1.05mse{c}^2$
• D. $1mse{c}^2$

Answer 1

Answer: (B)

$0.5mse{c}^2$

As the toy jumps off the balance , the normal force acting on the balance is going to increase which is given as $1.05kg$

So, initially when the toy was at rest the normal force was $m\times g=10N$.

So, the change in force because of the jump $=1.05g-10=0.5N$

So, the acceleration is $a=\frac{F}{m}=\frac{0.5}{1}=0.5m/s^2$