A spring when loaded has a potential energy ' $E .$ ' Then ' $m$ ' turns out of ' $n$ ' turns are removed from the spring. If the same load is suspended, then the energy stored in the spring is :

\frac{n}{(n - m)} E

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\frac{m E}{n}

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\frac{(n - m)}{m} E

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\frac{(n - m)}{n} E

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Solution

The correct option is D $\frac{(n - m)}{n} E$

Energy stored in spring is proportional to
number of turms
$\Rightarrow E α n$
$∴ \frac{E}{E^{1}} = \frac{n}{(n - m)}$
$\Rightarrow E^{1} = \frac{(n - m) E}{n}$

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A spring when loaded has a potential energy 'E.' Then 'm' turns out of 'n' turns are removed from the spring. If the same load is suspended, then the energy stored in the spring is :

The correct option is D (n−m)nE Energy stored in spring is proportional tonumber of turms⇒Eαn∴EE1=n(n−m)⇒E1=(n−m)En

A spring when loaded has a potential energy ' $E .$ ' Then ' $m$ ' turns out of ' $n$ ' turns are removed from the spring. If the same load is suspended, then the energy stored in the spring is :

The correct option is D $\frac{(n - m)}{n} E$

Energy stored in spring is proportional to
number of turms
$\Rightarrow E α n$
$∴ \frac{E}{E^{1}} = \frac{n}{(n - m)}$
$\Rightarrow E^{1} = \frac{(n - m) E}{n}$