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Question

A spy report about a suspected car reads as follows. "The car moved 2.00 km towards east, made a perpendicular left turn, ran for 500 m, made a perpendicular right turn, ran for 4.00 km and stopped". Find the displacement of the car.

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Solution

The displacement of the car is represented by AD.
AD=2i^+0.5j^+4i^ =6i^+0.5j^

Magnitude of AD is given by

AD=AE2+DE2 =62+0.52 =36+0.25=6.02 km



Now, tan θ=DEAE=112
θ=tan-1 112
Hence, the displacement of the car is 6.02 km along the direction tan-1 112 with positive the x-axis.

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