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Question

a=32+1321 then the value of a3+3a2 is__

A
3
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B
0
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C
2
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D
1
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Solution

The correct option is B 0
a=32+1321
cubing both sides, we get
a3=(32+1321)3
a3=2+12+13×32+1×321((32+1321))
a3=23×321a
a3=23a
a3+3a2=0

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