Question

A square $ABCD$ is inscribed in a circle of radius $10$ units. Find the area of the circle not included in the square. ( use $\pi =3.14$).

Answer 1

radius$=10$ units

Diagonal of square$=20$ units

Required area$=$area of circle $-$ area of square.

$=(\pi r^2-\frac{1}{2}{d}_1\times d_2)sq.unit=(\pi \times {10}^2-\frac{1}{2}\times 20\times 20)sq.unit$

$=(100\pi -200)$ sq. units

$=(100\times 3.14-200)$ sq. units

$=(314-200)$ sq.units

$=114$ sq.units