A square and a parallelogram have the same area. If a side of the square is $40 m$ and the height of the parallelogram is $20 m,$ find the base of the parallelogram.

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Solution

Side of square $40 m$
Area of square $a^{2} = 40 \times 40 = 1600 m^{2}$
The height of parallelogram $20 m$

Square and parallelogram have the same area

So, Area of the parallelogram

$1600 = 20 \times B a s e B a s e = \frac{1600}{20} B a s e = 80 m$

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A square and a parallelogram have the same area. If a side of the square is 40m and the height of the parallelogram is 20m, find the base of the parallelogram.

Side of square 40mArea of square a2=40×40=1600m2The height of parallelogram 20mSquare and parallelogram have the same area So, Area of the parallelogram 1600=20×BaseBase=160020Base=80m

A square and a parallelogram have the same area. If a side of the square is $40 m$ and the height of the parallelogram is $20 m,$ find the base of the parallelogram.

Side of square $40 m$
Area of square $a^{2} = 40 \times 40 = 1600 m^{2}$
The height of parallelogram $20 m$

Square and parallelogram have the same area

So, Area of the parallelogram

$1600 = 20 \times B a s e B a s e = \frac{1600}{20} B a s e = 80 m$