A square and a quadrilateral triangle have a side in common- If side of triangle is 34 cm long- Find the perimeter of figure formed-

[ AB= 3 4 cm; perimeter of given figure; ...

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Standard IX

Mathematics

Area of a Quadrilateral

A square and ...

Question

A square and a quadrilateral triangle have a side in common. If side of triangle is $\frac{3}{4} c m$ long. Find the perimeter of figure formed.

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Solution

$\begin{matrix} A B = \frac{3}{4} c m p e r i m e t e r o f g i v e n f i g u r e A B + B D + D E + E C + A C = \frac{3}{4} c m + \frac{3}{4} c m + \frac{3}{4} c m + \frac{3}{4} c m + \frac{3}{4} c m = 5 \times \frac{3}{4} = \frac{15}{4} = 3 \frac{3}{4} c m \end{matrix}$

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A square and a quadrilateral triangle have a side in common. If side of triangle is 34 cm long. Find the perimeter of figure formed.

AB=34cmperimeterofgivenfigureAB+BD+DE+EC+AC=34cm+34cm+34cm+34cm+34cm=5×34=154=334cm

A square and a quadrilateral triangle have a side in common. If side of triangle is $\frac{3}{4} c m$ long. Find the perimeter of figure formed.

$\begin{matrix} A B = \frac{3}{4} c m p e r i m e t e r o f g i v e n f i g u r e A B + B D + D E + E C + A C = \frac{3}{4} c m + \frac{3}{4} c m + \frac{3}{4} c m + \frac{3}{4} c m + \frac{3}{4} c m = 5 \times \frac{3}{4} = \frac{15}{4} = 3 \frac{3}{4} c m \end{matrix}$