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Question

A square and a regular hexagon have equal perimeters. Their areas are in the ratio:

A
2:1
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B
23:1
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C
3:2
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D
3:2
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Solution

The correct option is C 3:2
Let the side of the square =a.
Perimeter of the square =4a
Let the side of the hexagon =b
Perimeter of the hexagon =6b
Given, 4a=6b=>a=32b
Area of the square =a2
Area of the hexagon =332b2
Now, Area of square : Area of hexagon = a2:332b2
(32b)2:332b2
94b2:332b2
94:332
3:2

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