Question

Question 111

A square and an equilateral triangle have a side in common. If the side of the triangle is $\frac{4}{3}$ cm long, find the perimeter of the figure formed (see the figure).

Answer 1

As square and equilateral triangle both have a common side, i.e. BC.
So, all the sides of square and triangle will be equal and of measure $\frac{4}{3}$ cm
$\therefore$ Perimeter fo the figure $=AB+BD+DE+EC+AC$
$=5\times AB=5\times \frac{4}{3}=\frac{20}{3}cm$