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Byju's Answer
Standard IX
Mathematics
Pythagoras Theorem
A square and ...
Question
A square and an equilateral triangle have equal perimeters. If the diagonal of the square is
12
√
2
c
m
,
then the area of the triangle is:
A
24
√
2
c
m
2
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B
24
√
3
c
m
2
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C
48
√
3
c
m
2
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D
64
√
3
c
m
2
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Solution
The correct option is
D
64
√
3
c
m
2
Let ABCD be a square.
Given, diagonal of the square
12
√
2
cm
.
Then, BD =
12
√
2
cm
∠
B
C
D
=
90
∘
(
∵
ABCD is a square)
Then, by Pythagoras' theorem, we have
2
(
D
C
)
2
=
(
12
√
2
)
2
⇒
D
C
2
=
144
×
2
2
⇒
D
C
=
12
cm
∴
Perimeter of square
=
4
(
12
)
=
48
c
m
(
∵
A
B
=
B
C
=
C
D
=
A
D
)
Given, the square and equilateral triangle have equal perimeters.
Perimeter of an equilateral triangle with side 'a' is 3a.
So,
3
a
=
48
⇒
a
=
48
3
=
16
cm
We know, area of an equilateral triangle with side 'a' is given by
√
3
4
a
2
.
∴
Area
=
√
3
4
(
16
)
2
=
√
3
4
×
16
×
16
=
64
√
3
cm
2
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