A square and the an equilateral triangle are inscribed in a circle If a and b denote the length of their sides then
A
a2=b22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a22=b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3b2=2a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3a2=2b2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D3a2=2b2 We have to express the radius of the circle in terms of a and b. a2=r2+r2 =2r2 ⇒r2=a22 ....(i) ACr=cos300⇒b2.1r=√32 ∴r=b√3 or ∴r2=b2√3 ...(ii) From (i) and (ii), we have a22=b23⇒3a2=2b2