A square coil of edge l having n turns carries a current i. It is placed on a smooth horizontal plate A magnetic field B parallel to one edge is applied. The total mass of coil is M. The minimum value of B for which the coil will tip over is
A
Mglin
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B
Mg2lin
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C
2Mglin
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D
none of these
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Solution
The correct option is BMg2lin Let the magnetic field be applied along AB. Forces on side AB and CD are zero respectively. Force on each side BC and DA is F=nilB where n is the no of turns and B is the magnetic field and l is the length of each side of the square coil. Total force is Ftotal=2nilB Ftotal balances the weight Mg of the coil. ∴2nilB=Mg B=Mg2nil