Question

A square coil of side 10 cm has 10 turns. It rotates in a magnetic field of induction 0.02 T and produces a maximum induced emf of 10 mV. Then the angular velocity of the coil is

• A. $0.5rad{s}^{-1}$
• B. $5rad{s}^{-1}$
• C. $5\pi rad{s}^{-1}$
• D. $0.2\pi rad{s}^{-1}$

Answer 1

The correct option is B $5rad{s}^{-1}$

$e_{max}=BAN\omega$
$10\times {10}^{-3}=0.02\times 100\times {10}^{-4}\times 10\times \omega$
$\omega =\frac{1}{0.2}=\frac{10}{2}=5rad{s}^{-1}$