Question

A square conducting coil of area $=100c{m}^2$ is placed normally inside a uniform magnetic field of ${10}^3$ $Wb{m}^{-2}$. The magnetic flux linked with the coil is ____________ Wb.

• A. $10$
• B. ${10}^{-5}$
• C. ${10}^5$
• D. $0$

Answer 1

Answer: (A)

$10$

Magnetic flus is given by $\overrightarrow{B}.\overrightarrow{A}$

$\Rightarrow$ $\varphi =BA\cos \theta$

Now given, $B={10}^{3}Wb{m}^{-2},A=100c{m}^2=0.01m^2,\theta =0^0$(Given coil is placed normally so area vector will be in the direction of field)

So, $\varphi ={10}^3\times 0.01\times \cos 0^0=10Wb$

Therefore, A is correct option.