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Question

A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is F, the net force on the remaining three arms of the loop is

A
3 F
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B
-F
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C
-3 F
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D
F
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Solution

The correct option is D -F
The force on the two arms parallel to the field is zero( since dl×B=0
Force on remaining arms =F since current direction changes for this arm.

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