A square hole of cross sectional area 4cm $^{2}$ is drilled across a cube with its length parallel to a side of the cube. If an edge of the cube measures 5 cms, what is the total surface area of the structure so formed?

158 cm²

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190 cm²

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166 cm²

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182 cm²

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Solution

The correct option is D 182 cm²
New SA = (original SA) + (SA of square channel formed through the cube) - (squares on 2 faces)

= (25x6) + (2x5x4) - (4+4) = 182 sq cms

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A square hole of cross sectional area 4cm2 is drilled across a cube with its length parallel to a side of the cube. If an edge of the cube measures 5 cms, what is the total surface area of the structure so formed?

The correct option is D 182 cm2New SA = (original SA) + (SA of square channel formed through the cube) - (squares on 2 faces) = (25x6) + (2x5x4) - (4+4) = 182 sq cms

A square hole of cross sectional area 4cm $^{2}$ is drilled across a cube with its length parallel to a side of the cube. If an edge of the cube measures 5 cms, what is the total surface area of the structure so formed?

The correct option is D 182 cm²
New SA = (original SA) + (SA of square channel formed through the cube) - (squares on 2 faces)

= (25x6) + (2x5x4) - (4+4) = 182 sq cms