A square is inscribed in a circle. If p1 is the probability that a randomly chosen point of the circle lies within the square and p2 is the probability taht the point lies outside the square, then
A
p1=p2
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B
p1>p2 and p12−p22<13
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C
p1<p2
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D
None of these
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Solution
The correct option is Dp1>p2 and p12−p22<13 If a is the radius of the circle, the area of the inscribed square =2a2 and p1=2a2πa2=2π,p2=1−p1=π−2π π<4 and so π−2<2 which gives p1>p2. p12−p22=(p1−p2)(p1+p2)=4−ππ<13 as 3<π<4.